What is the general solution for 5-10sin(2x)=0 ?

The general solution for 5-10sin(2x)=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin

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5-10sin(2x)=0

5 - 10 sin (2 x) = 0

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

5 - 10 sin (2 x) = 0

Move

5

to the right side

- 10 sin (2 x) = - 5

Divide both sides by

- 10

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

x, cos (3 x) = 0

9 cos (2 θ) = 8

cos (2 θ) + 6 sin^{2} (θ) = 4, 0 \leq θ < 2 π

tan (x) = \frac{6}{9}

3 csc (θ) - 2 = 0

What is the general solution for 5-10sin(2x)=0 ?
The general solution for 5-10sin(2x)=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin