What is the general solution for solvefor y,z=cos(y) ?

The general solution for solvefor y,z=cos(y) is y=arccos(z)+2pin,y=-arccos(z)+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,z=cos(y)

solve for

y, z = cos (y)

y = arccos (z) + 2 πn, y = - arccos (z) + 2 πn

Solution steps

z = cos (y)

Switch sides

cos (y) = z

Apply trig inverse properties

y = arccos (z) + 2 πn, y = - arccos (z) + 2 πn

cos (x) = \frac{64}{83}

2 sin (z) = 1

cos (\frac{π}{2} - θ) = - sin (θ)

tan^{2} (x) + tan (x) = 0, 0 \leq x \leq 2 π

sin (y) + 2 = 0

What is the general solution for solvefor y,z=cos(y) ?
The general solution for solvefor y,z=cos(y) is y=arccos(z)+2pin,y=-arccos(z)+2pin