What is the general solution for 2sin(2x-pi/3)=1 ?

The general solution for 2sin(2x-pi/3)=1 is x=pin+pi/4 ,x=pin+(7pi)/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(2x-pi/3)=1

2 sin (2 x - \frac{π}{3}) = 1

x = πn + \frac{π}{4}, x = πn + \frac{7 π}{12}

Solution steps

2 sin (2 x - \frac{π}{3}) = 1

Divide both sides by

2

sin (2 x - \frac{π}{3}) = \frac{1}{2}

General solutions for

sin (2 x - \frac{π}{3}) = \frac{1}{2}

2 x - \frac{π}{3} = \frac{π}{6} + 2 πn, 2 x - \frac{π}{3} = \frac{5 π}{6} + 2 πn

Solve

2 x - \frac{π}{3} = \frac{π}{6} + 2 πn : x = πn + \frac{π}{4}

Solve

2 x - \frac{π}{3} = \frac{5 π}{6} + 2 πn : x = πn + \frac{7 π}{12}

x = πn + \frac{π}{4}, x = πn + \frac{7 π}{12}

sin (x) = \frac{15}{23}

4 sin^{2} (x) = 3, + [0, + 2 π]

6 sin (θ) - 1 = 4 sin (θ)

cot^{3} (x) = cot^{3} (x) sin (x)

3 (1 - cos (x)) = sin^{2} (x)

What is the general solution for 2sin(2x-pi/3)=1 ?
The general solution for 2sin(2x-pi/3)=1 is x=pin+pi/4 ,x=pin+(7pi)/(12)