What is the general solution for 9(1-sin(θ))=9 ?

The general solution for 9(1-sin(θ))=9 is θ=2pin,θ=pi+2pin

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9(1-sin(θ))=9

9 (1 - sin (θ)) = 9

θ = 2 πn, θ = π + 2 πn

Solution steps

9 (1 - sin (θ)) = 9

Divide both sides by

9

1 - sin (θ) = 1

Move

1

to the right side

- sin (θ) = 0

Divide both sides by

- 1

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

sin (θ) = \frac{15.226}{10.6}

cos (4 x) - 1 = sin (4 x)

csc^{2} (x) - csc (x) - 20 = 0

(sin (x) - 1) (2 sin (x) + 1) = 0

0 = arctan (x)

What is the general solution for 9(1-sin(θ))=9 ?
The general solution for 9(1-sin(θ))=9 is θ=2pin,θ=pi+2pin