What is the general solution for 0=4sin(2x) ?

The general solution for 0=4sin(2x) is x=pin,x= pi/2+pin

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0=4sin(2x)

0 = 4 sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = 4 sin (2 x)

Switch sides

4 sin (2 x) = 0

Divide both sides by

4

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

\frac{sin ( 112. 8 ^{\circ} )}{16.1} = \frac{sin ( x )}{12.2}

(sin (x) + cos (x))^{2} = \frac{3}{2}

2 sin^{2} (t) - sin (t) - 1 = 0

cos (x) = - \frac{1}{5 2}

cot (x) tan (2 x) = 3

What is the general solution for 0=4sin(2x) ?
The general solution for 0=4sin(2x) is x=pin,x= pi/2+pin