What is the general solution for cos(4x)=1,0<= x<= pi/2 ?

The general solution for cos(4x)=1,0<= x<= pi/2 is x=0,x= pi/2

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cos(4x)=1,0<= x<= pi/2

cos (4 x) = 1, 0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{π}{2}

Solution steps

cos (4 x) = 1, 0 \leq x \leq \frac{π}{2}

General solutions for

cos (4 x) = 1

4 x = 0 + 2 πn

Solve

4 x = 0 + 2 πn : x = \frac{πn}{2}

x = \frac{πn}{2}

Solutions for the range

0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{π}{2}

sec (x) = - 4

g, θ (t) = - 1 cos (\frac{g}{l} t)

sec (x) = - 3

2 tan (x) csc (x) + 2 csc (x) + tan (x) + 1 = 0

csc (x) + cot (x) = 3, 0 \leq x \leq 2 π

What is the general solution for cos(4x)=1,0<= x<= pi/2 ?
The general solution for cos(4x)=1,0<= x<= pi/2 is x=0,x= pi/2