What is the general solution for cos(2θ)=(-sqrt(3))/2 ?

The general solution for cos(2θ)=(-sqrt(3))/2 is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin

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cos(2θ)=(-sqrt(3))/2

cos (2 θ) = \frac{- 3}{2}

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

Solution steps

cos (2 θ) = \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

cos (2 θ) = - \frac{3}{2}

General solutions for

cos (2 θ) = - \frac{3}{2}

2 θ = \frac{5 π}{6} + 2 πn, 2 θ = \frac{7 π}{6} + 2 πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

Solve

2 θ = \frac{7 π}{6} + 2 πn : θ = \frac{7 π}{12} + πn

θ = \frac{5 π}{12} + πn, θ = \frac{7 π}{12} + πn

cos (θ) = 0.65

- \frac{2}{3} sin (x) + \frac{1}{3} sin (2 x) = 0

cos (θ) = 0.84

cos (θ) = 0.88

cos (θ) = 0.76

What is the general solution for cos(2θ)=(-sqrt(3))/2 ?
The general solution for cos(2θ)=(-sqrt(3))/2 is θ=(5pi)/(12)+pin,θ=(7pi)/(12)+pin