What is the general solution for 2sin^2(θ)-3sin(θ)=0 ?

The general solution for 2sin^2(θ)-3sin(θ)=0 is θ=2pin,θ=pi+2pin

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2sin^2(θ)-3sin(θ)=0

2 sin^{2} (θ) - 3 sin (θ) = 0

θ = 2 πn, θ = π + 2 πn

Solution steps

2 sin^{2} (θ) - 3 sin (θ) = 0

Solve by substitution

sin (θ) = \frac{3}{2}, sin (θ) = 0

sin (θ) = \frac{3}{2} :

No Solution

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

\frac{cos ( x )}{1 + sin ( x )} + tan (x) = cos (x)

sin (2 x) = 2 cos^{2} (x), 0 \leq x \leq 2 π

2 sin (x) + 1 = cos (2 x)

sin (2 x) = - 1 sin (x)

cos (x) = \frac{1}{6}

What is the general solution for 2sin^2(θ)-3sin(θ)=0 ?
The general solution for 2sin^2(θ)-3sin(θ)=0 is θ=2pin,θ=pi+2pin