What is the general solution for cos(2x)+sin(2x)=-1 ?

The general solution for cos(2x)+sin(2x)=-1 is x=pin+pi/2 ,x=pin+(3pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x)+sin(2x)=-1

cos (2 x) + sin (2 x) = - 1

x = πn + \frac{π}{2}, x = πn + \frac{3 π}{4}

Solution steps

cos (2 x) + sin (2 x) = - 1

Rewrite using trig identities

2 sin (2 x + \frac{π}{4}) = - 1

Divide both sides by

2

sin (2 x + \frac{π}{4}) = - \frac{2}{2}

General solutions for

sin (2 x + \frac{π}{4}) = - \frac{2}{2}

2 x + \frac{π}{4} = \frac{5 π}{4} + 2 πn, 2 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn

Solve

2 x + \frac{π}{4} = \frac{5 π}{4} + 2 πn : x = πn + \frac{π}{2}

Solve

2 x + \frac{π}{4} = \frac{7 π}{4} + 2 πn : x = πn + \frac{3 π}{4}

x = πn + \frac{π}{2}, x = πn + \frac{3 π}{4}

5 cot (x) + 3 = - 2

2 sin^{2} (x) - cos (x) = 0

3 cos (x) (sin (x) + tan (x)) = 2 (1 + cos (x))

cos (x) = \frac{8.8}{13}

tan^{2} (θ) + 7 tan (θ) + 8 = 0

What is the general solution for cos(2x)+sin(2x)=-1 ?
The general solution for cos(2x)+sin(2x)=-1 is x=pin+pi/2 ,x=pin+(3pi)/4