What is the value of sin(20)cos(40)+cos(20)sin(40) ?

The value of sin(20)cos(40)+cos(20)sin(40) is (sqrt(3))/2

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sin(20)cos(40)+cos(20)sin(40)

sin (2 0^{\circ}) cos (4 0^{\circ}) + cos (2 0^{\circ}) sin (4 0^{\circ})

\frac{3}{2}

Solution steps

sin (2 0^{\circ}) cos (4 0^{\circ}) + cos (2 0^{\circ}) sin (4 0^{\circ})

Rewrite using trig identities:

sin (6 0^{\circ})

= sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

= \frac{3}{2}

sin (60 0^{\circ})

arccsc (0)

cos (5 9^{\circ})

- sec^{2} (0)

sec (arctan (\frac{3}{3}))

What is the value of sin(20)cos(40)+cos(20)sin(40) ?
The value of sin(20)cos(40)+cos(20)sin(40) is (sqrt(3))/2