What is the general solution for cos(θ)= 4/5 ,sin(θ) ?

The general solution for cos(θ)= 4/5 ,sin(θ) is No Solution for θ\in\mathbb{R}

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cos(θ)= 4/5 ,sin(θ)

cos (θ) = \frac{4}{5}, sin (θ)

No Solution for θ \in R

Solution steps

cos (θ) = \frac{4}{5}, sin (θ)

Apply trig inverse properties

θ = arccos (\frac{4}{5}) + 2 πn, θ = 2 π - arccos (\frac{4}{5}) + 2 πn

Solutions for the range

sin (θ)

No Solution for θ \in R

3 cos (2 θ) - 3 cos (θ) + 3 = 4 cos (θ) + 10

cos (x) = \frac{1}{18}

2 sin (2 x) cos (x) - sin (x) = 0

4 sin (\frac{θ}{2}) = 4 cos (\frac{θ}{2})

2 sec (x) + 4 = sec (x) + 6

What is the general solution for cos(θ)= 4/5 ,sin(θ) ?
The general solution for cos(θ)= 4/5 ,sin(θ) is No Solution for θ\in\mathbb{R}