What is the general solution for sin^2(x)-5sin(x)=0 ?

The general solution for sin^2(x)-5sin(x)=0 is x=2pin,x=pi+2pin

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sin^2(x)-5sin(x)=0

sin^{2} (x) - 5 sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

sin^{2} (x) - 5 sin (x) = 0

Solve by substitution

sin (x) = 5, sin (x) = 0

sin (x) = 5 :

No Solution

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

7 tan (c) + 7 = 2 tan (c) + 1

cos (2 x) cos (x) - sin (2 x) sin (x) = 1

sin (x - \frac{π}{2}) = - \frac{2}{2}

cos (x) = \frac{1}{10}

- 8 sin (θ) + 5 = 5

What is the general solution for sin^2(x)-5sin(x)=0 ?
The general solution for sin^2(x)-5sin(x)=0 is x=2pin,x=pi+2pin