What is the general solution for sin(x)-sin(x)*cos(x)=0,0<= x<= 2pi ?

The general solution for sin(x)-sin(x)*cos(x)=0,0<= x<= 2pi is x=0,x=pi,x=2pi

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sin(x)-sin(x)*cos(x)=0,0<= x<= 2pi

sin (x) - sin (x) \cdot cos (x) = 0, 0 \leq x \leq 2 π

x = 0, x = π, x = 2 π

Solution steps

sin (x) - sin (x) cos (x) = 0, 0 \leq x \leq 2 π

Factor

sin (x) - sin (x) cos (x) : - sin (x) (cos (x) - 1)

- sin (x) (cos (x) - 1) = 0

Solving each part separately

sin (x) = 0 or cos (x) - 1 = 0

sin (x) = 0, 0 \leq x \leq 2 π : x = 0, x = π, x = 2 π

cos (x) - 1 = 0, 0 \leq x \leq 2 π : x = 0, x = 2 π

Combine all the solutions

x = 0, x = π, x = 2 π

8 sin (x) + 6 cos (x) = 8

4 sin (x) + 5 = 0

12 arctan (x) = 4 π

2 tan^{2} (x) - 5 tan (x) + 3 = 0

sin (x) = \frac{2}{9}

What is the general solution for sin(x)-sin(x)*cos(x)=0,0<= x<= 2pi ?
The general solution for sin(x)-sin(x)*cos(x)=0,0<= x<= 2pi is x=0,x=pi,x=2pi