What is the general solution for sin(x^2-2x+1)=1 ?

The general solution for sin(x^2-2x+1)=1 is x=(4+sqrt(32pin+8pi))/4 ,x=(4-sqrt(32pin+8pi))/4

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sin(x^2-2x+1)=1

sin (x^{2} - 2 x + 1) = 1

x = \frac{4 + 32 πn + 8 π}{4}, x = \frac{4 - 32 πn + 8 π}{4}

Solution steps

sin (x^{2} - 2 x + 1) = 1

General solutions for

sin (x^{2} - 2 x + 1) = 1

x^{2} - 2 x + 1 = \frac{π}{2} + 2 πn

Solve

x^{2} - 2 x + 1 = \frac{π}{2} + 2 πn : x = \frac{4 + 32 πn + 8 π}{4}, x = \frac{4 - 32 πn + 8 π}{4}

x = \frac{4 + 32 πn + 8 π}{4}, x = \frac{4 - 32 πn + 8 π}{4}

3 - tan^{2} (x) = 0

2 sin^{2} (θ) + cos (θ) = 0

csc (θ) = - \frac{8}{5}

cos^{2} (x) = 2 cos (x) + 3

3 sin (x) - cos (x) = 3

What is the general solution for sin(x^2-2x+1)=1 ?
The general solution for sin(x^2-2x+1)=1 is x=(4+sqrt(32pin+8pi))/4 ,x=(4-sqrt(32pin+8pi))/4