What is the general solution for sqrt(1-cos(2x))=0 ?

The general solution for sqrt(1-cos(2x))=0 is x=pin

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sqrt(1-cos(2x))=0

1 - cos (2 x) = 0

x = πn

Solution steps

1 - cos (2 x) = 0

Square both sides:

1 - cos (2 x) = 0

1 - cos (2 x) = 0

Solve

1 - cos (2 x) = 0 : cos (2 x) = 1

cos (2 x) = 1

Verify Solutions:

cos (2 x) = 1

True

The solution is

cos (2 x) = 1

General solutions for

cos (2 x) = 1

2 x = 0 + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

x = πn

sin (2 x) cos (x) = cos (x)

- sin (2 x) sin (x) + cos (2 x) cos (x) = cos (x)

cos (x) = \frac{7}{16}

3 = - 2 cos (θ)

4 sin (3 x) = 2

What is the general solution for sqrt(1-cos(2x))=0 ?
The general solution for sqrt(1-cos(2x))=0 is x=pin