What is the general solution for tan(2x-pi/6)=(-1)/(sqrt(3)) ?

The general solution for tan(2x-pi/6)=(-1)/(sqrt(3)) is x=(pin)/2+pi/2

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tan(2x-pi/6)=(-1)/(sqrt(3))

tan (2 x - \frac{π}{6}) = \frac{- 1}{3}

x = \frac{πn}{2} + \frac{π}{2}

Solution steps

tan (2 x - \frac{π}{6}) = \frac{- 1}{3}

Simplify

\frac{- 1}{3} : - \frac{3}{3}

General solutions for

tan (2 x - \frac{π}{6}) = - \frac{3}{3}

2 x - \frac{π}{6} = \frac{5 π}{6} + πn

Solve

2 x - \frac{π}{6} = \frac{5 π}{6} + πn : x = \frac{πn}{2} + \frac{π}{2}

x = \frac{πn}{2} + \frac{π}{2}

2 cos (x) + 2 sin (x) = 1

sin (θ) = \frac{2}{13}, cos (θ) = \frac{3}{13}

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6 sin^{2} (x) + 4 sin (x) - 1 = 0

cos (x - \frac{π}{4}) + sin (x + \frac{π}{4}) = 0

What is the general solution for tan(2x-pi/6)=(-1)/(sqrt(3)) ?
The general solution for tan(2x-pi/6)=(-1)/(sqrt(3)) is x=(pin)/2+pi/2