What is the general solution for (cos^2(x)-4)/(cos(x)-2)=1 ?

The general solution for (cos^2(x)-4)/(cos(x)-2)=1 is x=pi+2pin

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(cos^2(x)-4)/(cos(x)-2)=1

\frac{cos ^{2} ( x ) - 4}{cos ( x ) - 2} = 1

x = π + 2 πn

Solution steps

\frac{cos ^{2} ( x ) - 4}{cos ( x ) - 2} = 1

Simplify

\frac{cos ^{2} ( x ) - 4}{cos ( x ) - 2} : cos (x) + 2

cos (x) + 2 = 1

Move

2

to the right side

cos (x) = - 1

General solutions for

cos (x) = - 1

x = π + 2 πn

- 8 sec^{2} (x) - 26 tan (x) = 12

tan (θ) = 0.3

tan (θ) = 0.8

sin (a) tan (a) = sin (a)

2 tan (x) + sec^{2} (x) = 0

What is the general solution for (cos^2(x)-4)/(cos(x)-2)=1 ?
The general solution for (cos^2(x)-4)/(cos(x)-2)=1 is x=pi+2pin