What is the general solution for sin(θ)+0.069=0 ?

The general solution for sin(θ)+0.069=0 is θ=-0.06905…+2pin,θ=pi+0.06905…+2pin

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sin(θ)+0.069=0

sin (θ) + 0.069 = 0

θ = - 0.06905 \dots + 2 πn, θ = π + 0.06905 \dots + 2 πn

Solution steps

sin (θ) + 0.069 = 0

Move

0.069

to the right side

sin (θ) = - 0.069

Apply trig inverse properties

θ = arcsin (- 0.069) + 2 πn, θ = π + arcsin (0.069) + 2 πn

Show solutions in decimal form

θ = - 0.06905 \dots + 2 πn, θ = π + 0.06905 \dots + 2 πn

tan (θ) = 1.3

tan (x) = 0.25

2 sec (x) sin (x) + 2 = 4 sin (x) + sec (x)

4 sin (x) cos (x) - 3 cos (x) = 0

sin (θ) = - 0.5, sec (θ - \frac{π}{2})

What is the general solution for sin(θ)+0.069=0 ?
The general solution for sin(θ)+0.069=0 is θ=-0.06905…+2pin,θ=pi+0.06905…+2pin