What is the general solution for cos(θ)= 7/25 ,(3pi)/2 <θ<2pi ?

The general solution for cos(θ)= 7/25 ,(3pi)/2 <θ<2pi is θ=2pi-1.28700…

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cos(θ)= 7/25 ,(3pi)/2 <θ<2pi

cos (θ) = \frac{7}{25}, \frac{3 π}{2} < θ < 2 π

θ = 2 π - 1.28700 \dots

Solution steps

cos (θ) = \frac{7}{25}, \frac{3 π}{2} < θ < 2 π

Apply trig inverse properties

θ = arccos (\frac{7}{25}) + 2 πn, θ = 2 π - arccos (\frac{7}{25}) + 2 πn

Solutions for the range

\frac{3 π}{2} < θ < 2 π

θ = 2 π - arccos (\frac{7}{25})

Show solutions in decimal form

θ = 2 π - 1.28700 \dots

5 (1 - sin (θ)) = 5

x, cos (x) = - 1

5 cos (θ) = 5 sin (- θ)

5 sin (x) + 1 = 3 sin (x)

cos (a) = \frac{3}{4}

What is the general solution for cos(θ)= 7/25 ,(3pi)/2 <θ<2pi ?
The general solution for cos(θ)= 7/25 ,(3pi)/2 <θ<2pi is θ=2pi-1.28700…