What is the general solution for 5cos(θ)=5sin(-θ) ?

The general solution for 5cos(θ)=5sin(-θ) is θ=(3pi)/4+pin

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5cos(θ)=5sin(-θ)

5 cos (θ) = 5 sin (- θ)

θ = \frac{3 π}{4} + πn

Solution steps

5 cos (θ) = 5 sin (- θ)

Rewrite using trig identities

5 cos (θ) = - 5 sin (θ)

Subtract

- 5 sin (θ)

from both sides

5 cos (θ) + 5 sin (θ) = 0

Rewrite using trig identities

5 + 5 tan (θ) = 0

Move

5

to the right side

5 tan (θ) = - 5

Divide both sides by

5

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

5 sin (x) + 1 = 3 sin (x)

cos (a) = \frac{3}{4}

∣ tan (x) ∣ = 1

3 sin (x) + 4 = 5 cos (x)

2 cos^{2} (x) + 5 sin (x) = 4, 0 \leq x \leq 2 π

What is the general solution for 5cos(θ)=5sin(-θ) ?
The general solution for 5cos(θ)=5sin(-θ) is θ=(3pi)/4+pin