What is the general solution for -2cos(C)+5=2cos(C)+4 ?

The general solution for -2cos(C)+5=2cos(C)+4 is C=1.31811…+2pin,C=2pi-1.31811…+2pin

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-2cos(C)+5=2cos(C)+4

- 2 cos (C) + 5 = 2 cos (C) + 4

C = 1.31811 \dots + 2 πn, C = 2 π - 1.31811 \dots + 2 πn

Solution steps

- 2 cos (C) + 5 = 2 cos (C) + 4

Solve by substitution

cos (C) = \frac{1}{4}

cos (C) = \frac{1}{4} : C = arccos (\frac{1}{4}) + 2 πn, C = 2 π - arccos (\frac{1}{4}) + 2 πn

Combine all the solutions

C = arccos (\frac{1}{4}) + 2 πn, C = 2 π - arccos (\frac{1}{4}) + 2 πn

Show solutions in decimal form

C = 1.31811 \dots + 2 πn, C = 2 π - 1.31811 \dots + 2 πn

2 cos^{2} (θ) + 2 sin (θ) - 12 = 9 sin (θ) - 7

2 csc^{2} (x) + cot^{2} (x) - 3 = 0

tan (x) = 0.095

θ, x = tan^{2} (θ)

sin^{2} (x) cos^{2} (x) = 1

What is the general solution for -2cos(C)+5=2cos(C)+4 ?
The general solution for -2cos(C)+5=2cos(C)+4 is C=1.31811…+2pin,C=2pi-1.31811…+2pin