What is the general solution for solvefor x,cos(kx)=-1 ?

The general solution for solvefor x,cos(kx)=-1 is x= pi/k+(2pin)/k ;\quad k\ne 0

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solvefor x,cos(kx)=-1

solve for

x, cos (k x) = - 1

x = \frac{π}{k} + \frac{2 πn}{k}; k \neq = 0

Solution steps

cos (k x) = - 1

General solutions for

cos (k x) = - 1

k x = π + 2 πn

Solve

k x = π + 2 πn : x = \frac{π}{k} + \frac{2 πn}{k}; k \neq = 0

x = \frac{π}{k} + \frac{2 πn}{k}; k \neq = 0

sec^{2} (x) = \frac{3}{4}

sin (x) = \frac{4.4 sin ( 11 9 ^{\circ} )}{12.3}

- sec^{2} (x) = 2 tan (x)

3 cot^{2} (x) - 1 = 0

sin (x) \cdot cos (x) = 1

What is the general solution for solvefor x,cos(kx)=-1 ?
The general solution for solvefor x,cos(kx)=-1 is x= pi/k+(2pin)/k ;\quad k\ne 0