What is the general solution for (2cos(x)+1)=0 ?

The general solution for (2cos(x)+1)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

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(2cos(x)+1)=0

(2 cos (x) + 1) = 0

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

(2 cos (x) + 1) = 0

Move

1

to the right side

2 cos (x) = - 1

Divide both sides by

2

cos (x) = - \frac{1}{2}

General solutions for

cos (x) = - \frac{1}{2}

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

3 cos (x) + 2 = 0

2 tan (x) sin (x) - tan (x) = 0

tan (\frac{x}{2}) = 5

- 6 cos (2 x) + 23 cos (x) - 11 = 0

sin^{2} (x + 4) = 1

What is the general solution for (2cos(x)+1)=0 ?
The general solution for (2cos(x)+1)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin