What is the general solution for 0=-sin(2x) ?

The general solution for 0=-sin(2x) is x=pin,x= pi/2+pin

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0=-sin(2x)

0 = - sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = - sin (2 x)

Switch sides

- sin (2 x) = 0

Divide both sides by

- 1

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

1 - sin^{2} (θ) = 0

x, z = y sin (x y)

2 sin^{2} (x) + csc^{2} (x) = 3

t, tan (t) = 2

sin (α) = \frac{8}{17}

What is the general solution for 0=-sin(2x) ?
The general solution for 0=-sin(2x) is x=pin,x= pi/2+pin