What is the general solution for 1-4sin^2(x)=0 ?

The general solution for 1-4sin^2(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=(7pi)/6+2pin,x=(11pi)/6+2pin

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1-4sin^2(x)=0

1 - 4 sin^{2} (x) = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

1 - 4 sin^{2} (x) = 0

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Combine all the solutions

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

cos (2 θ) - 6 sin^{2} (θ) = - 5

sin (A) = \frac{15}{17}

9 sin (x) = 0

cos (θ) = \frac{20}{25}

cos^{2} (x) + 2 sin (x) cos (x) - sin^{2} (x) = 0

What is the general solution for 1-4sin^2(x)=0 ?
The general solution for 1-4sin^2(x)=0 is x= pi/6+2pin,x=(5pi)/6+2pin,x=(7pi)/6+2pin,x=(11pi)/6+2pin