What is the general solution for tan(2θ)-sqrt(3)=0 ?

The general solution for tan(2θ)-sqrt(3)=0 is θ= pi/6+(pin)/2

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tan(2θ)-sqrt(3)=0

tan (2 θ) - 3 = 0

θ = \frac{π}{6} + \frac{πn}{2}

Solution steps

tan (2 θ) - 3 = 0

Move

3

to the right side

tan (2 θ) = 3

General solutions for

tan (2 θ) = 3

2 θ = \frac{π}{3} + πn

Solve

2 θ = \frac{π}{3} + πn : θ = \frac{π}{6} + \frac{πn}{2}

θ = \frac{π}{6} + \frac{πn}{2}

sin (x) = 30

2 tan^{2} (x) + 9 tan (x) + 7 = 0

sec (x) = sin^{2} (x) sec (x)

cos (5 t) - cos (3 t) = sin (4 t)

2 sin^{2} (θ) - 1 = 0, 0 \leq θ < 2 π

What is the general solution for tan(2θ)-sqrt(3)=0 ?
The general solution for tan(2θ)-sqrt(3)=0 is θ= pi/6+(pin)/2