What is the general solution for sec(4x)-9=0 ?

The general solution for sec(4x)-9=0 is x=(1.45945…)/4+(pin)/2 ,x= pi/2-(1.45945…)/4+(pin)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(4x)-9=0

sec (4 x) - 9 = 0

x = \frac{1.45945 \dots}{4} + \frac{πn}{2}, x = \frac{π}{2} - \frac{1.45945 \dots}{4} + \frac{πn}{2}

Solution steps

sec (4 x) - 9 = 0

Move

9

to the right side

sec (4 x) = 9

Apply trig inverse properties

4 x = arcsec (9) + 2 πn, 4 x = 2 π - arcsec (9) + 2 πn

Solve

4 x = arcsec (9) + 2 πn : x = \frac{arcsec ( 9 )}{4} + \frac{πn}{2}

Solve

4 x = 2 π - arcsec (9) + 2 πn : x = \frac{π}{2} - \frac{arcsec ( 9 )}{4} + \frac{πn}{2}

x = \frac{arcsec ( 9 )}{4} + \frac{πn}{2}, x = \frac{π}{2} - \frac{arcsec ( 9 )}{4} + \frac{πn}{2}

Show solutions in decimal form

x = \frac{1.45945 \dots}{4} + \frac{πn}{2}, x = \frac{π}{2} - \frac{1.45945 \dots}{4} + \frac{πn}{2}

\frac{1}{3} cos (θ) = - \frac{3}{6}

sin (\frac{x}{2}) + cos (\frac{x}{2}) = 1

cos (2 x) = 3 sin (2 x)

3 sin (2 x - 1 5^{\circ}) = cos (2 x - 1 5^{\circ})

sec (\frac{x}{2}) - 2 = 0

What is the general solution for sec(4x)-9=0 ?
The general solution for sec(4x)-9=0 is x=(1.45945…)/4+(pin)/2 ,x= pi/2-(1.45945…)/4+(pin)/2