What is the general solution for 2cos^2(x)+sin^2(x)=0 ?

The general solution for 2cos^2(x)+sin^2(x)=0 is No Solution for x\in\mathbb{R}

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2cos^2(x)+sin^2(x)=0

2 cos^{2} (x) + sin^{2} (x) = 0

No Solution for x \in R

Solution steps

2 cos^{2} (x) + sin^{2} (x) = 0

Rewrite using trig identities

2 - sin^{2} (x) = 0

Solve by substitution

sin (x) = 2, sin (x) = - 2

sin (x) = 2 :

No Solution

sin (x) = - 2 :

No Solution

Combine all the solutions

No Solution for x \in R

9.383 = 3.1915 cos (\frac{π}{6 ( 1 - c )}) + 6.1915

tan (2 x) = - \frac{40}{3}

3 cos (2 x) - 5 sin (x) + 1 = 0

tan (θ) = \frac{5}{- 2}

sin (x + \frac{π}{2}) = \frac{1}{2}

What is the general solution for 2cos^2(x)+sin^2(x)=0 ?
The general solution for 2cos^2(x)+sin^2(x)=0 is No Solution for x\in\mathbb{R}