What is the general solution for 6=6(1-sin(θ)) ?

The general solution for 6=6(1-sin(θ)) is θ=2pin,θ=pi+2pin

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6=6(1-sin(θ))

6 = 6 (1 - sin (θ))

θ = 2 πn, θ = π + 2 πn

Solution steps

6 = 6 (1 - sin (θ))

Switch sides

6 (1 - sin (θ)) = 6

Divide both sides by

6

1 - sin (θ) = 1

Move

1

to the right side

- sin (θ) = 0

Divide both sides by

- 1

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

tan (x) = 3, - π \leq x < π

4 cos (x) - 4 sin (x) = 0

3 csc (3 x) = - 2

2 cos (2 θ) + 1 = - 12 cos (θ) - 6

- 3 cos (2 θ) - 9 cos (θ) - 2 = 2 cos (θ) - 6

What is the general solution for 6=6(1-sin(θ)) ?
The general solution for 6=6(1-sin(θ)) is θ=2pin,θ=pi+2pin