What is the general solution for 7sin(θ/2)=-7cos(θ/2) ?

The general solution for 7sin(θ/2)=-7cos(θ/2) is θ=(3pi)/2+2pin

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7sin(θ/2)=-7cos(θ/2)

7 sin (\frac{θ}{2}) = - 7 cos (\frac{θ}{2})

θ = \frac{3 π}{2} + 2 πn

Solution steps

7 sin (\frac{θ}{2}) = - 7 cos (\frac{θ}{2})

Rewrite using trig identities

7 tan (\frac{θ}{2}) = - 7

Divide both sides by

7

tan (\frac{θ}{2}) = - 1

General solutions for

tan (\frac{θ}{2}) = - 1

\frac{θ}{2} = \frac{3 π}{4} + πn

Solve

\frac{θ}{2} = \frac{3 π}{4} + πn : θ = \frac{3 π}{2} + 2 πn

θ = \frac{3 π}{2} + 2 πn

p, e^{x} - sin (p \frac{x}{3}) = 0

2 cos (x) + cos (2 x) \cdot 2 = 0

3 sin^{2} (t) - 7 sin (t) - 6 = 0

sin (s) = - \frac{2}{2}

cos^{2} (θ) + 2 cos (θ) + 1 = 0, 0 \leq θ < 2 π

What is the general solution for 7sin(θ/2)=-7cos(θ/2) ?
The general solution for 7sin(θ/2)=-7cos(θ/2) is θ=(3pi)/2+2pin