What is the general solution for sin^2(x)+2sin(x)=0 ?

The general solution for sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin

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sin^2(x)+2sin(x)=0

sin^{2} (x) + 2 sin (x) = 0

x = 2 πn, x = π + 2 πn

Solution steps

sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - 2

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 2 :

No Solution

Combine all the solutions

x = 2 πn, x = π + 2 πn

cos (2 x) - 7 cos (x) + 4 = 0

\frac{87.17}{sin ( 12 0 ^{\circ} )} = \frac{40}{sin ( x )}

23 tan (x) - 2 = 0

2 cos (x) 2 = 0

cos^{2} (x) - 6 cos (x) = - 9

What is the general solution for sin^2(x)+2sin(x)=0 ?
The general solution for sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin