What is the general solution for solvefor y,x=cos(2y) ?

The general solution for solvefor y,x=cos(2y) is y=(arccos(x))/2+pin,y=-(arccos(x))/2+pin

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solvefor y,x=cos(2y)

solve for

y, x = cos (2 y)

y = \frac{arccos ( x )}{2} + πn, y = - \frac{arccos ( x )}{2} + πn

Solution steps

x = cos (2 y)

Switch sides

cos (2 y) = x

Apply trig inverse properties

2 y = arccos (x) + 2 πn, 2 y = - arccos (x) + 2 πn

Solve

2 y = arccos (x) + 2 πn : y = \frac{arccos ( x )}{2} + πn

Solve

2 y = - arccos (x) + 2 πn : y = - \frac{arccos ( x )}{2} + πn

y = \frac{arccos ( x )}{2} + πn, y = - \frac{arccos ( x )}{2} + πn

tan (x) = \frac{a}{b}

- 1 = cot (θ)

6 sin^{2} (A) - 5 sin (A) + 1 = 0

x, arcsin (3 x - 4 y) = \frac{π}{2}

sin (x) a = \frac{π}{3}

What is the general solution for solvefor y,x=cos(2y) ?
The general solution for solvefor y,x=cos(2y) is y=(arccos(x))/2+pin,y=-(arccos(x))/2+pin