What is the general solution for tan^2(θ)+4tan(θ)=0 ?

The general solution for tan^2(θ)+4tan(θ)=0 is θ=pin,θ=-1.32581…+pin

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tan^2(θ)+4tan(θ)=0

tan^{2} (θ) + 4 tan (θ) = 0

θ = πn, θ = - 1.32581 \dots + πn

Solution steps

tan^{2} (θ) + 4 tan (θ) = 0

Solve by substitution

tan (θ) = 0, tan (θ) = - 4

tan (θ) = 0 : θ = πn

tan (θ) = - 4 : θ = arctan (- 4) + πn

Combine all the solutions

θ = πn, θ = arctan (- 4) + πn

Show solutions in decimal form

θ = πn, θ = - 1.32581 \dots + πn

7 cos (θ) = 7 cos (2 θ)

3 cos (2 x) = 3 cos (x)

sin^{2} (2 x) = 3 cos^{2} (2 x)

- 2 sin (θ) = 2 sin (2 θ)

cos (θ) = \frac{π}{2}

What is the general solution for tan^2(θ)+4tan(θ)=0 ?
The general solution for tan^2(θ)+4tan(θ)=0 is θ=pin,θ=-1.32581…+pin