What is the general solution for sqrt(3)sec(2θ)=2 ?

The general solution for sqrt(3)sec(2θ)=2 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sqrt(3)sec(2θ)=2

3 sec (2 θ) = 2

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

Solution steps

3 sec (2 θ) = 2

Divide both sides by

3

sec (2 θ) = \frac{2 3}{3}

General solutions for

sec (2 θ) = \frac{2 3}{3}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{11 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{11 π}{6} + 2 πn : θ = \frac{11 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{11 π}{12} + πn

2 sin^{2} (x) + 3 sin (x) - 1 = 0

- 6 cos^{2} (θ) + cos (θ) + 7 = 5

y, arccot (x y) = ln (sin (x))

tan (α) = - \frac{3}{4}

sec (2 x) csc (2 x) = 2 csc (2 x), 0 \leq x \leq 2 π

What is the general solution for sqrt(3)sec(2θ)=2 ?
The general solution for sqrt(3)sec(2θ)=2 is θ= pi/(12)+pin,θ=(11pi)/(12)+pin