What is the general solution for 6tan^2(x)-18=0 ?

The general solution for 6tan^2(x)-18=0 is x= pi/3+pin,x=(2pi)/3+pin

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6tan^2(x)-18=0

6 tan^{2} (x) - 18 = 0

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

Solution steps

6 tan^{2} (x) - 18 = 0

Solve by substitution

tan (x) = 3, tan (x) = - 3

tan (x) = 3 : x = \frac{π}{3} + πn

tan (x) = - 3 : x = \frac{2 π}{3} + πn

Combine all the solutions

x = \frac{π}{3} + πn, x = \frac{2 π}{3} + πn

11 sin^{2} (θ) - 5 sin (θ) = 4

cos (\frac{π x}{4}) = \frac{1}{2}

x, cos (2 x) = 1

5 cos (x) cot (x) = 1

2 cos^{2} (x) = - 1

What is the general solution for 6tan^2(x)-18=0 ?
The general solution for 6tan^2(x)-18=0 is x= pi/3+pin,x=(2pi)/3+pin