What is the general solution for cos(6x)=1,0<= x<= pi/2 ?

The general solution for cos(6x)=1,0<= x<= pi/2 is x=0,x= pi/3

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cos(6x)=1,0<= x<= pi/2

cos (6 x) = 1, 0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{π}{3}

Solution steps

cos (6 x) = 1, 0 \leq x \leq \frac{π}{2}

General solutions for

cos (6 x) = 1

6 x = 0 + 2 πn

Solve

6 x = 0 + 2 πn : x = \frac{πn}{3}

x = \frac{πn}{3}

Solutions for the range

0 \leq x \leq \frac{π}{2}

x = 0, x = \frac{π}{3}

cos^{2} (θ) + 2 cos (θ) - 3 = 0

3 + 6 sin (3 t) = 0

cos (2 θ) = 11 sin (θ) - 5

- sin (2 x) sin (x) + cos (x) = 0

x, sec (x) = - 3.5

What is the general solution for cos(6x)=1,0<= x<= pi/2 ?
The general solution for cos(6x)=1,0<= x<= pi/2 is x=0,x= pi/3