What is the general solution for tan^2(θ)+8tan(θ)+9=0 ?

The general solution for tan^2(θ)+8tan(θ)+9=0 is θ=-0.93474…+pin,θ=-1.42144…+pin

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tan^2(θ)+8tan(θ)+9=0

tan^{2} (θ) + 8 tan (θ) + 9 = 0

θ = - 0.93474 \dots + πn, θ = - 1.42144 \dots + πn

Solution steps

tan^{2} (θ) + 8 tan (θ) + 9 = 0

Solve by substitution

tan (θ) = - 4 + 7, tan (θ) = - 4 - 7

tan (θ) = - 4 + 7 : θ = arctan (- 4 + 7) + πn

tan (θ) = - 4 - 7 : θ = arctan (- 4 - 7) + πn

Combine all the solutions

θ = arctan (- 4 + 7) + πn, θ = arctan (- 4 - 7) + πn

Show solutions in decimal form

θ = - 0.93474 \dots + πn, θ = - 1.42144 \dots + πn

2 tan^{2} (x) - 1 = 3 tan (x)

8 csc^{2} (x) - 2 cot (x) = 9

cos (d) = \frac{9}{15}

coth^{2} (x) + csch^{2} (x) = 2

tan (x) = \frac{3}{9}

What is the general solution for tan^2(θ)+8tan(θ)+9=0 ?
The general solution for tan^2(θ)+8tan(θ)+9=0 is θ=-0.93474…+pin,θ=-1.42144…+pin