What is the general solution for cos(θ)= 1/(sqrt(5)) ?

The general solution for cos(θ)= 1/(sqrt(5)) is θ=1.10714…+2pin,θ=2pi-1.10714…+2pin

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cos(θ)= 1/(sqrt(5))

cos (θ) = \frac{1}{5}

θ = 1.10714 \dots + 2 πn, θ = 2 π - 1.10714 \dots + 2 πn

Solution steps

cos (θ) = \frac{1}{5}

Simplify

\frac{1}{5} : \frac{5}{5}

Apply trig inverse properties

θ = arccos (\frac{5}{5}) + 2 πn, θ = 2 π - arccos (\frac{5}{5}) + 2 πn

Show solutions in decimal form

θ = 1.10714 \dots + 2 πn, θ = 2 π - 1.10714 \dots + 2 πn

sin^{2} (x) - 3 cos (x) + 3 = 0

cot^{2} (x) = cot^{2} (x) - 2 cot (x)

cos (x) = \frac{4}{10}

16 cos (2 x) - 4 = 0

- csc (x) cot (x) = 0

What is the general solution for cos(θ)= 1/(sqrt(5)) ?
The general solution for cos(θ)= 1/(sqrt(5)) is θ=1.10714…+2pin,θ=2pi-1.10714…+2pin