What is the general solution for 10sin(A)+16=3sin(A)+9 ?

The general solution for 10sin(A)+16=3sin(A)+9 is A=(3pi)/2+2pin

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10sin(A)+16=3sin(A)+9

10 sin (A) + 16 = 3 sin (A) + 9

A = \frac{3 π}{2} + 2 πn

Solution steps

10 sin (A) + 16 = 3 sin (A) + 9

Solve by substitution

sin (A) = - 1

sin (A) = - 1 : A = \frac{3 π}{2} + 2 πn

Combine all the solutions

A = \frac{3 π}{2} + 2 πn

y, x = cos (y)

tan^{2} (x) - 2 tan (x) - 5 = 0

tan (x) = \frac{10}{11}

sin (θ) = \frac{9}{13}

tan^{2} (x) - sin^{2} (x) = 0

What is the general solution for 10sin(A)+16=3sin(A)+9 ?
The general solution for 10sin(A)+16=3sin(A)+9 is A=(3pi)/2+2pin