What is the general solution for (sin(t)-1)cos(t)=0 ?

The general solution for (sin(t)-1)cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

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(sin(t)-1)cos(t)=0

(sin (t) - 1) cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Solution steps

(sin (t) - 1) cos (t) = 0

Solving each part separately

sin (t) - 1 = 0 or cos (t) = 0

sin (t) - 1 = 0 : t = \frac{π}{2} + 2 πn

cos (t) = 0 : t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Combine all the solutions

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

csc (x) = 1, 0 \leq x \leq 2 π

4 sin (θ) + 33 = 3

cos (2 x) - 2 sin (x) = 0

sin (x) - 4 cos (x) = 0

2 sin (x) + 53 = 63

What is the general solution for (sin(t)-1)cos(t)=0 ?
The general solution for (sin(t)-1)cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin