What is the general solution for tan((2θ)/3)+sqrt(3)=0 ?

The general solution for tan((2θ)/3)+sqrt(3)=0 is θ=pi+(3pin)/2

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tan((2θ)/3)+sqrt(3)=0

tan (\frac{2 θ}{3}) + 3 = 0

θ = π + \frac{3 πn}{2}

Solution steps

tan (\frac{2 θ}{3}) + 3 = 0

Move

3

to the right side

tan (\frac{2 θ}{3}) = - 3

General solutions for

tan (\frac{2 θ}{3}) = - 3

\frac{2 θ}{3} = \frac{2 π}{3} + πn

Solve

\frac{2 θ}{3} = \frac{2 π}{3} + πn : θ = π + \frac{3 πn}{2}

θ = π + \frac{3 πn}{2}

sin (x) - 6 = cos (x) - 6

sin (θ) = 0.529

4 sin (x) - 2 csc (x) = 0

2 sin (2 x) = - 1, 0 < x < 2 π

4 sin (x) - 1 = 2

What is the general solution for tan((2θ)/3)+sqrt(3)=0 ?
The general solution for tan((2θ)/3)+sqrt(3)=0 is θ=pi+(3pin)/2