What is the general solution for sin((2θ)/3)=0 ?

The general solution for sin((2θ)/3)=0 is θ=3pin,θ=(3pi)/2+3pin

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sin((2θ)/3)=0

sin (\frac{2 θ}{3}) = 0

θ = 3 πn, θ = \frac{3 π}{2} + 3 πn

Solution steps

sin (\frac{2 θ}{3}) = 0

General solutions for

sin (\frac{2 θ}{3}) = 0

\frac{2 θ}{3} = 0 + 2 πn, \frac{2 θ}{3} = π + 2 πn

Solve

\frac{2 θ}{3} = 0 + 2 πn : θ = 3 πn

Solve

\frac{2 θ}{3} = π + 2 πn : θ = \frac{3 π}{2} + 3 πn

θ = 3 πn, θ = \frac{3 π}{2} + 3 πn

3 sec^{2} (x) - 6 = 0

sin (x) = \frac{6}{19}

- 2 sin (x) cos (x) + 3 cos (x) = sin (x) + 3 cos (x)

4 sin^{2} (x) - 4 cos^{2} (x) = 23

sec^{2} (θ) = 1

What is the general solution for sin((2θ)/3)=0 ?
The general solution for sin((2θ)/3)=0 is θ=3pin,θ=(3pi)/2+3pin