What is the general solution for 4sin(2x)=-2 ?

The general solution for 4sin(2x)=-2 is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin

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4sin(2x)=-2

4 sin (2 x) = - 2

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

Solution steps

4 sin (2 x) = - 2

Divide both sides by

4

sin (2 x) = - \frac{1}{2}

General solutions for

sin (2 x) = - \frac{1}{2}

2 x = \frac{7 π}{6} + 2 πn, 2 x = \frac{11 π}{6} + 2 πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

Solve

2 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{12} + πn

x = \frac{7 π}{12} + πn, x = \frac{11 π}{12} + πn

x, sin^{2} (x) = 0

cos (t) = - \frac{3}{4}

sin (2 x) - 2 cos (x) = 2 sin (x) - 1

cos^{2} (θ) - \frac{3}{2} cos (2 θ) = 0

sinh (x) = \frac{3}{4}, cosh (x)

What is the general solution for 4sin(2x)=-2 ?
The general solution for 4sin(2x)=-2 is x=(7pi)/(12)+pin,x=(11pi)/(12)+pin