What is the general solution for 17arccos(x)-4pi=arccos(x) ?

The general solution for 17arccos(x)-4pi=arccos(x) is x=(sqrt(2))/2

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17arccos(x)-4pi=arccos(x)

17 arccos (x) - 4 π = arccos (x)

x = \frac{2}{2}

Solution steps

17 arccos (x) - 4 π = arccos (x)

Solve by substitution

arccos (x) = \frac{π}{4}

arccos (x) = \frac{π}{4} : x = \frac{2}{2}

Combine all the solutions

x = \frac{2}{2}

cos (6 x) - cos (3 x) = 0

sin (4 θ) = - \frac{1}{2}

cos (x) = \frac{3}{4}

cos^{2} (x) + \frac{3}{2} sin (2 x) = 0

7 cos (2 x) = 7 cos (x)

What is the general solution for 17arccos(x)-4pi=arccos(x) ?
The general solution for 17arccos(x)-4pi=arccos(x) is x=(sqrt(2))/2