What is the general solution for 6arccos(3x)=5pi ?

The general solution for 6arccos(3x)=5pi is x=-1/(2sqrt(3))

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6arccos(3x)=5pi

6 arccos (3 x) = 5 π

x = - \frac{1}{2 3}

Solution steps

6 arccos (3 x) = 5 π

Divide both sides by

6

arccos (3 x) = \frac{5 π}{6}

Apply trig inverse properties

3 x = - \frac{3}{2}

Solve

3 x = - \frac{3}{2} : x = - \frac{1}{2 3}

x = - \frac{1}{2 3}

2 sin (θ) = - 3, 36 0^{\circ}, 18 0^{\circ} \leq θ

tan (θ) = \frac{- 3}{4}

sin (2 x) cos (x) = cos (2 x) sin (x)

sin (x) = \frac{7}{12}

sin (x) = \frac{7}{13}

What is the general solution for 6arccos(3x)=5pi ?
The general solution for 6arccos(3x)=5pi is x=-1/(2sqrt(3))