What is the general solution for 3cos(11θ)=0 ?

The general solution for 3cos(11θ)=0 is θ= pi/(22)+(2pin)/(11),θ=(3pi)/(22)+(2pin)/(11)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos(11θ)=0

3 cos (11 θ) = 0

θ = \frac{π}{22} + \frac{2 πn}{11}, θ = \frac{3 π}{22} + \frac{2 πn}{11}

Solution steps

3 cos (11 θ) = 0

Divide both sides by

3

cos (11 θ) = 0

General solutions for

cos (11 θ) = 0

11 θ = \frac{π}{2} + 2 πn, 11 θ = \frac{3 π}{2} + 2 πn

Solve

11 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{22} + \frac{2 πn}{11}

Solve

11 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{22} + \frac{2 πn}{11}

θ = \frac{π}{22} + \frac{2 πn}{11}, θ = \frac{3 π}{22} + \frac{2 πn}{11}

cos (2 a) = - 1

cos^{2} (θ) - 6 cos (θ) + 1 = 0

4 = 6 sec (x)

cot (3 θ) + 1 = csc (3 θ)

sin (a) = - \frac{1}{2}

What is the general solution for 3cos(11θ)=0 ?
The general solution for 3cos(11θ)=0 is θ= pi/(22)+(2pin)/(11),θ=(3pi)/(22)+(2pin)/(11)