What is the general solution for 6arccos(4x)=pi ?

The general solution for 6arccos(4x)=pi is x=(sqrt(3))/8

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6arccos(4x)=pi

6 arccos (4 x) = π

x = \frac{3}{8}

Solution steps

6 arccos (4 x) = π

Divide both sides by

6

arccos (4 x) = \frac{π}{6}

Apply trig inverse properties

4 x = \frac{3}{2}

Solve

4 x = \frac{3}{2} : x = \frac{3}{8}

x = \frac{3}{8}

- 4 sin (x) cos (x) = 2 sin (x)

7 sin^{2} (θ) + 16 sin (θ) + 9 = 0

3 tan (\frac{3 π}{4} (x + \frac{3 π}{2})) = 1

tan (x) = \frac{10}{4}

3 tan^{2} (x) + 11 tan (x) + 8 = 0

What is the general solution for 6arccos(4x)=pi ?
The general solution for 6arccos(4x)=pi is x=(sqrt(3))/8