What is the general solution for cos(θ)= 3/5 ,(3pi)/2 <θ<2pi ?

The general solution for cos(θ)= 3/5 ,(3pi)/2 <θ<2pi is θ=2pi-0.92729…

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cos(θ)= 3/5 ,(3pi)/2 <θ<2pi

cos (θ) = \frac{3}{5}, \frac{3 π}{2} < θ < 2 π

θ = 2 π - 0.92729 \dots

Solution steps

cos (θ) = \frac{3}{5}, \frac{3 π}{2} < θ < 2 π

Apply trig inverse properties

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Solutions for the range

\frac{3 π}{2} < θ < 2 π

θ = 2 π - arccos (\frac{3}{5})

Show solutions in decimal form

θ = 2 π - 0.92729 \dots

cos (2 x) = \frac{3}{2}

- 3 cos (2 θ) + 2 sin (θ) + 5 = 9 sin (θ)

3 + sin (x) = 5 cos (2 x)

cos (x) = \frac{15}{20}

a sin (x) + b cos (x) = 0

What is the general solution for cos(θ)= 3/5 ,(3pi)/2 <θ<2pi ?
The general solution for cos(θ)= 3/5 ,(3pi)/2 <θ<2pi is θ=2pi-0.92729…