What is the general solution for sin(2pi*1.5x)=0 ?

The general solution for sin(2pi*1.5x)=0 is x=(2n)/3 ,x= 1/3+(2n)/3

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sin(2pi*1.5x)=0

sin (2 π \cdot 1.5 x) = 0

x = \frac{2 n}{3}, x = \frac{1}{3} + \frac{2 n}{3}

Solution steps

sin (2 π 1.5 x) = 0

General solutions for

sin (2 π 1.5 x) = 0

2 π 1.5 x = 0 + 2 πn, 2 π 1.5 x = π + 2 πn

Solve

2 π 1.5 x = 0 + 2 πn : x = \frac{2 n}{3}

Solve

2 π 1.5 x = π + 2 πn : x = \frac{1}{3} + \frac{2 n}{3}

x = \frac{2 n}{3}, x = \frac{1}{3} + \frac{2 n}{3}

sin (15 x) + cos (15 x) = 0

1 + 2 sin (\frac{t ^{2}}{2}) = 0

3 tan^{2} (x) - 2 = csc^{2} (x) - cot^{2} (x)

sin (3 θ) = - \frac{3}{2}

x, arctan (\frac{y}{x}) = 0

What is the general solution for sin(2pi*1.5x)=0 ?
The general solution for sin(2pi*1.5x)=0 is x=(2n)/3 ,x= 1/3+(2n)/3