What is the general solution for cos(x)=-1,0<= x<2pi ?

The general solution for cos(x)=-1,0<= x<2pi is x=pi

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cos(x)=-1,0<= x<2pi

cos (x) = - 1, 0 \leq x < 2 π

x = π

Solution steps

cos (x) = - 1, 0 \leq x < 2 π

General solutions for

cos (x) = - 1

x = π + 2 πn

Solutions for the range

0 \leq x < 2 π

x = π

2 cos^{2} (x) - 3 sin (x) - 2 = 0

4 sin (x) cos^{2} (x) = cos (x)

cos (x) = 3 sin (x)

tan (23 θ) + cot (23 θ) = \frac{4}{3}

tan^{2} (x) + 1 = sec (x)

What is the general solution for cos(x)=-1,0<= x<2pi ?
The general solution for cos(x)=-1,0<= x<2pi is x=pi